Prevent Vue.use to be used without options parameter unless it's specified as optional (with `?`)

[bitPogo]

What problem does this feature solve?

Reproduction link
Please see: https://tinyurl.com/y5mlgqqh

Steps to reproduce

1. write a plugin
2. overload Vue.use ( see the given link above for detail )

What is expected?
During compiling it fails, because the types are not matching.

What is actually happening?
It compiles without errors

What does the proposed API look like?

A possible solution is to change the type in vue/types/vue VueConstructor to:

use(plugin: PluginObject<unknown> | PluginFunction<unknown>, ...options: unknown[]): VueConstructor<V>;

See: https://tinyurl.com/y6anfs8b

[posva]

Vue.use is already typesafe. You shouldn't override it, Provide the MessagePluginOptions to the generic of PluginFunction like this: https://github.com/vuejs/vuefire/blob/master/packages/vuefire/src/firestore.ts#L104-L107

[bitPogo]

Thanks for the advise but it still not satisfy all constrains which are intended in the change. Please see: https://tinyurl.com/y2aksjmw
( It would be nice if you would not close the issue right away )

[posva]

Okay, sorry, it took me some time to understand what you meant. Next time, make sure to correctly point what isn't working instead of saying it compiles without errors. I'm updating the title to reflect the intention. This is an easy PR and you already found the solution, can you send a PR with the change and the test? If you cannot that's fine, I will do it.

[bitPogo]

Thanks for your politeness! I try to make a more clearer description next time! Is there any chanel, if I have question, to poke you?

[posva]

if you need help with the PR message me on Discord but you are pretty much done with https://tinyurl.com/y6anfs8b 🙂