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#148 - Lambda arguments should be locals when the lambda is a local. #150

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#148 - Lambda arguments should be locals when the lambda is a local. #150

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4 changes: 2 additions & 2 deletions packages/pyright-scip/snapshots/output/single_function/src/single_function.py
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Original file line number Diff line number Diff line change
Expand Up @@ -18,10 +18,10 @@ def my_cool_function_2(a: str):
x = ", world"
# ^ definition local 1
return (lambda y: a + x + y)("oh no")
# ^ definition local 2(y)
# ^ definition local 3
# ^ reference snapshot-util 0.1 `src.single_function`/my_cool_function_2().(a)
# ^ reference local 1
# ^ reference local 2(y)
# ^ reference local 3

def next_level():
# ^^^^^^^^^^ definition snapshot-util 0.1 `src.single_function`/next_level().
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9 changes: 8 additions & 1 deletion packages/pyright-scip/src/treeVisitor.ts
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Expand Up @@ -1090,8 +1090,15 @@ export class TreeVisitor extends ParseTreeWalker {
log.debug('Paramerter with no name', node);
return ScipSymbol.local(this.counter.next());
}
// If the parent is a lambda, we can't generate a legal symbol
// by appending a descriptor; the parameter needs to be a local
// too.
const parentSymbol = this.getScipSymbol(node.parent!);
if (parentSymbol.isLocal()) {
return ScipSymbol.local(this.counter.next());
}

return Symbols.makeParameter(this.getScipSymbol(node.parent!), node.name.value);
return Symbols.makeParameter(parentSymbol, node.name.value);
}
case ParseNodeType.Class: {
return Symbols.makeType(this.getScipSymbol(node.parent!), (node as ClassNode).name.value);
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