Improve quoted pattern type inference #8766
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Types a splice applied to some arguments `$f(arg1, ..., argn)` in a quote pattern. The tree is desugared into `$f.apply(arg1, ..., argn)` where the expression `$f` is expected to type as a function type `(T1, ..., Tn) => R`. `Ti` is the type of the argument `argi` and R if the type of the prototype. The prototype must be fully defined to be able to infer the type of `R`.
odersky
approved these changes
Apr 27, 2020
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Types a splice applied to some arguments
$f(arg1, ..., argn)in a quote pattern.The tree is desugared into
$f.apply(arg1, ..., argn)where the expression$fis expected to type as a function type
(T1, ..., Tn) => R.Tiis the type of the argumentargiand R if the type of the prototype.The prototype must be fully defined to be able to infer the type of
R.This way we can rewrite the pattern
${f: Int => Int}(3)to$f(3)or$f(3): Int(if the result type is not known).