Closed
Description
For Shape, there is not getter for the dimension stored inside the structure. There was one, but now it is solely a comment (see below):
impl<D> Shape<D>
where
D: Dimension,
{
// Return a reference to the dimension
//pub fn dimension(&self) -> &D { &self.dim }
/// Return the size of the shape in number of elements
pub fn size(&self) -> usize {
self.dim.size()
}
}Is there a possibility to extract the exact dimension stored inside Shape to use it to modify the dimensions of struct definitions (minimal example below) outside of the crate?
struct Tester<D: Dimension> {
weight: Array<f64, D::Larger>,
}
impl Tester<Ix1> {
fn new<Sh>(shape: Sh, first_dim: usize) -> Self
where
Sh: ShapeBuilder<Dim = Ix1>,
{
let dim_in = shape.into_shape().dim; // This is not possible because the field `dim` is private. How can one obtain the dimension?
let shape_new = Shape::from(Ix2(first_dim, dim[0]));
let weight = Array::<f64, Ix2>::zeros(new);
// ... modify `weight` ...
Self { weight }
}
}