Find all the texts which is 'Normal' style and font size is NOT 11 in a docx file using python-docx

[priyamsaha]

from docx.api import Document
import pandas as pd
from docx.shared import Pt

texts = []
sizes = []
document = Document('new.docx')
for p in document.paragraphs:
    for run in p.runs:
        if p.style.name.startswith("Normal") and run.font.size != Pt(11):
            texts.append(run.text)
print(texts)

I am trying to validate a document, I want all the texts in the document where the font style is 'Normal' and font size is NOT 11. The above code seems to give output where font size is 11 as well. Is there a alternative to this? Thanks in advance!

[prcantwell]

Is the default document font size 11 points? python-docx will leave font.size as None to indicate that "the font size should be inherited from the style hierarchy" (which I assume means it will be inherited from the default document style). This is mentioned in the docs for docx.text.run.Font.size, and it would explain why 11 point font is showing up in your output, since None is not equal to Pt(11).

To find runs with font size not equal to 11 points (assuming this is the default font size), try replacing run.font.size != Pt(11) with run.font.size is not None in your code.

To find the default font size for your document, you can run the following code snippet, which will print the XML for the document defaults (this code snippet assumes that the document file name is new.docx):

from docx.api import Document

document = Document('new.docx')

xml = document.styles.element.xml
xml_lines = xml.splitlines()

print("<!-- DOCUMENT DEFAULTS -->")
document_defaults_flag = False
for line in xml_lines:
    if "<w:docDefaults>" in line:
        document_defaults_flag = True
    if document_defaults_flag is True:
        print(line)
    if "</w:docDefaults>" in line:
        document_defaults_flag = False
print("<!-- END DOCUMENT DEFAULTS -->")

When I run this snippet, I get the following output:

<!-- DOCUMENT DEFAULTS -->
  <w:docDefaults>
    <w:rPrDefault>
      <w:rPr>
        <w:rFonts w:asciiTheme="minorHAnsi" w:eastAsiaTheme="minorEastAsia" w:hAnsiTheme="minorHAnsi" w:cstheme="minorBidi"/>
        <w:sz w:val="22"/>
        <w:szCs w:val="22"/>
        <w:lang w:val="en-US" w:eastAsia="en-US" w:bidi="ar-SA"/>
      </w:rPr>
    </w:rPrDefault>
    <w:pPrDefault>
      <w:pPr>
        <w:spacing w:after="200" w:line="276" w:lineRule="auto"/>
      </w:pPr>
    </w:pPrDefault>
  </w:docDefaults>
<!-- END DOCUMENT DEFAULTS -->

I believe that the line with <w:sz w:val="22"/> shows that the default document font size is 11 points, because w:sz specifies the font size in half-point values (22 half points is 11 points -- see the Microsoft API reference for the FontSize Class in DocumentFormat.OpenXml.Wordprocessing). Also see Microsoft API reference for the DocDefaults Class, i.e., <w:docDefaults>

As far as I can tell, the default document font size is not available through the python-dotx API, so I don't think there's a better option than just replacing run.font.size != Pt(11) with run.font.size is not None in your code. (I searched the documentation and source code for usages of "<w:docDefaults>" and "w:docDefaults" and couldn't find any code that exposes the default font size from the line <w:sz w:val="22"/>.)

I'm a new user of python-docx, and not an expert in Word or XML, so take all of this with a grain of salt. I've been looking into similar issues and this is what I've figured out so far.