`pt.linalg.det` should eagerly fail if known shapes are not square

[jessegrabowski]

Description

The following graph is invalid:

x = pt.tensor('x', shape=(5,3)
y = pt.linalg.det(x)

This will happily construct a graph, but it will always fail at runtime when the perform method is called, because the numpy implementation will raise an error. There's no reason we can't check add a check to make_node testing if 1) the shape of the input is known and, 2) if it is valid.