php extension and "CFLAGS=.. -Og ..."

[aotto1968]

Description

Hi, I maintain a PHP extension and recognize after the embedding of the PHP autoconf extension a bug in the makefile:

> grep -- '-g\>' Makefile
CFLAGS = -g g -Wall -Wcast-align -Wfatal-errors -O0
CXXFLAGS = -g g -Wall -Wcast-align -Wfatal-errors -g -O0

→ as you see the -g g is invalid, the question is: where it comes from ?

I add some debug prints into the configure and end up with:

checking if debug is enabled... yes
checking if zts is enabled... no
44 ++++++++++++++++++++ CFLAGS=-g -Og -Wall -Wcast-align -Wfatal-errors
55 ++++++++++++++++++++ CFLAGS=-g g -Wall -Wcast-align -Wfatal-errors
checking for gawk... gawk
checking for 'ZTS'... no

the problem in configure was the SED ... it does NOT recognize the -Og option :

if test "$PHP_DEBUG" = "yes"; then
  PHP_DEBUG=1
  ZEND_DEBUG=yes

echo "44 ++++++++++++++++++++ CFLAGS=$CFLAGS"

  CFLAGS=`echo "$CFLAGS" | $SED -e 's/-O[0-9s]*//g'`
  CXXFLAGS=`echo "$CXXFLAGS" | $SED -e 's/-O[0-9s]*//g'`

echo "55 ++++++++++++++++++++ CFLAGS=$CFLAGS"

    if test "$GCC" = "yes" || test "$ICC" = "yes"; then
    CFLAGS="$CFLAGS -O0"
    CXXFLAGS="$CXXFLAGS -g -O0"
  fi
  if test "$SUNCC" = "yes"; then
    if test -n "$auto_cflags"; then
      CFLAGS="-g"
      CXXFLAGS="-g"
    else
      CFLAGS="$CFLAGS -g"
      CXXFLAGS="$CFLAGS -g"
    fi
  fi
else
  PHP_DEBUG=0
  ZEND_DEBUG=no
fi

the source is from configure.ac created by phpize

PHP Version

PHP 8.1.10

Operating System

openSUSE Tumbleweed

[petk]

Hello, @aotto1968, can you create a step by step instructions how this happens exactly? For example, which extension are we talking about here and what steps are taken for the compilation?