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Description
These are the commands I ran in IPython:
In [1]: import pandas as pd
In [2]: df = pd.DataFrame(data={'x': [1,2,3]})
In [3]: df.to_parquet('test.parquet')
In [4]: with open('test.parquet', 'rb') as f:
...: df2 = pd.read_parquet(f)
...:
At which point it exits IPython without displaying an error or stacktrace. Maybe this is some kind of segfault? It also fails when running from a script, and also when reading from a BytesIO instead of a file.
This is using pandas==1.2.0, pyarrow==2.0.0, and Python 3.7.3. Also this was run in Windows from Powershell.
If it helps, this is the output from pd.show_versions()
:
INSTALLED VERSIONS
------------------
commit : 3e89b4c4b1580aa890023fc550774e63d499da25
python : 3.7.3.final.0
python-bits : 64
OS : Windows
OS-release : 10
Version : 10.0.17763
machine : AMD64
processor : Intel64 Family 6 Model 45 Stepping 7, GenuineIntel
byteorder : little
LC_ALL : None
LANG : None
LOCALE : None.None
pandas : 1.2.0
numpy : 1.19.4
pytz : 2020.5
dateutil : 2.8.1
pip : 20.3.3
setuptools : 51.1.0.post20201221
Cython : 0.29.14
pytest : None
hypothesis : None
sphinx : 2.0.0
blosc : None
feather : None
xlsxwriter : 1.1.5
lxml.etree : 4.4.2
html5lib : None
pymysql : None
psycopg2 : None
jinja2 : 2.11.2
IPython : 7.4.0
pandas_datareader: None
bs4 : 4.7.1
bottleneck : None
fsspec : None
fastparquet : None
gcsfs : None
matplotlib : 3.1.1
numexpr : None
odfpy : None
openpyxl : None
pandas_gbq : None
pyarrow : 2.0.0
pyxlsb : None
s3fs : None
scipy : 1.3.1
sqlalchemy : 1.3.2
tables : None
tabulate : None
xarray : None
xlrd : None
xlwt : None
numba : None