Description
When plotting with a TimedeltaIndex
with a fixed frequency and xmin > xmax
, a ValueError gets raised.
>>> pd.Series([1,2], index=pd.timedelta_range(start=0, periods=2, freq='D')).plot(xlim=(3, 1))
C:\ProgramData\Miniconda3\envs\env_name\lib\site-packages\pandas\plotting_matplotlib\converter.py in call(self, x, pos)
1066 def call(self, x, pos=0) -> str:
1067 (vmin, vmax) = tuple(self.axis.get_view_interval())
-> 1068 n_decimals = int(np.ceil(np.log10(100 * 1e9 / (vmax - vmin))))
1069 if n_decimals > 9:
1070 n_decimals = 9ValueError: cannot convert float NaN to integer
Seems that there should just be an abs
in this line.
I would expect this to be able to output a plot successfully.
Works fine with a TimedeltaIndex
with freq=None
:
pd.Series([1,2], index=[pd.Timedelta(days=1), pd.Timedelta(days=2)]).plot(xlim=(3, 1))
INSTALLED VERSIONS
commit : db08276
python : 3.8.6.final.0
python-bits : 64
OS : Windows
OS-release : 10
Version : 10.0.18362
machine : AMD64
processor : Intel64 Family 6 Model 94 Stepping 3, GenuineIntel
byteorder : little
LC_ALL : None
LANG : None
LOCALE : English_United States.1252
pandas : 1.1.3
numpy : 1.19.2
pytz : 2020.1
dateutil : 2.8.1
pip : 20.2.3
setuptools : 49.6.0.post20201009
Cython : None
pytest : 6.1.1
hypothesis : None
sphinx : 3.2.1
blosc : None
feather : None
xlsxwriter : None
lxml.etree : None
html5lib : None
pymysql : None
psycopg2 : 2.8.6 (dt dec pq3 ext lo64)
jinja2 : 2.11.2
IPython : 7.18.1
pandas_datareader: None
bs4 : None
bottleneck : None
fsspec : None
fastparquet : None
gcsfs : None
matplotlib : 3.3.2
numexpr : 2.7.1
odfpy : None
openpyxl : None
pandas_gbq : None
pyarrow : 1.0.1
pytables : None
pyxlsb : None
s3fs : None
scipy : 1.5.0
sqlalchemy : 1.3.20
tables : 3.6.1
tabulate : None
xarray : None
xlrd : None
xlwt : None
numba : None