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Description
Is your feature request related to a problem?
It is currently possible to perform arithmetic on an Interval iff it is an Interval of numbers. For Interval iv, iv - c == Interval(iv.left-c, iv.right-c). This does not work for intervals of Timestamps:
In [90]: iv = pd.Interval(3, 4)
In [91]: pd.Interval(iv.left-2, iv.right-2)
Out[91]: Interval(1, 2, closed='right')
In [92]: iv - 2
Out[92]: Interval(1, 2, closed='right')
In [93]: iv = pd.Interval(pd.Timestamp("1900-01-01"), pd.Timestamp("1900-01-02"))
In [94]: pd.Interval(iv.left - pd.Timestamp("1900-01-01"), iv.right - pd.Timestamp("1900-01-0
...: 1"))
Out[94]: Interval(Timedelta('0 days 00:00:00'), Timedelta('1 days 00:00:00'), closed='right')
In [95]: iv - pd.Timestamp("1900-01-01")
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-95-b61ec78c0d66> in <module>
----> 1 iv - pd.Timestamp("1900-01-01")
TypeError: unsupported operand type(s) for -: 'pandas._libs.interval.Interval' and 'Timestamp'
Describe the solution you'd like
I would like that the behaviour that iv - b == Interval(iv.left-b, iv.right-b) holds for all types that Interval can hold, including Timestamps and Timedeltas.
API breaking implications
No backward compatibility issues expected.
Describe alternatives you've considered
Users can currently resort to Interval(iv.left-b, iv.right-b). This is more typing and required repeating the expression b.