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__idiv__ creates a copy? #12962

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@hhuuggoo

Description

@hhuuggoo

Code Sample, a copy-pastable example if possible

import pandas as pd
mylist = [pd.Series([1,2,3])]

for m in mylist:
    m /= 2.0
    print '***printing m***'
    print m
print
print '***mylist[0] - should be same as m, but isnt***'
print mylist[0]

observed output:

***printing m***
0    0.5
1    1.0
2    1.5
dtype: float64

***mylist[0] - should be same as m, but isnt***
0    1
1    2
2    3
dtype: int64

Expected Output

***printing m***
0    1
1    2
2    3
dtype: float64

***mylist[0] - should be same as m, but isnt***
0    1
1    2
2    3
dtype: int64

output of pd.show_versions()

INSTALLED VERSIONS

commit: None
python: 2.7.11.final.0
python-bits: 64
OS: Darwin
OS-release: 14.5.0
machine: x86_64
processor: i386
byteorder: little
LC_ALL: None
LANG: None

pandas: 0.18.0
nose: None
pip: 8.1.1
setuptools: 20.6.7
Cython: None
numpy: 1.11.0
scipy: None
statsmodels: None
xarray: None
IPython: None
sphinx: None
patsy: None
dateutil: 2.5.2
pytz: 2016.3
blosc: None
bottleneck: None
tables: None
numexpr: None
matplotlib: None
openpyxl: None
xlrd: None
xlwt: None
xlsxwriter: None
lxml: None
bs4: None
html5lib: None
httplib2: None
apiclient: None
sqlalchemy: None
pymysql: None
psycopg2: None
jinja2: None
boto: None

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    BugDtype ConversionsUnexpected or buggy dtype conversionsNumeric OperationsArithmetic, Comparison, and Logical operations

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