Closed
Description
Describe the bug
The timedelta_range
and interval_range
functions should accept a pandas.Timedelta
or datetime.timedelta
object as the freq
argument.
To Reproduce
Example:
import pandas
def foo(step: float):
return pandas.timedelta_range(
start=pandas.Timedelta(0),
periods=10,
freq=pandas.Timedelta(seconds=step),
)
Using mypy foo.py
:
foo.py:7: error: Argument "freq" to "timedelta_range" has incompatible type "Timedelta"; expected "Union[str, DateOffset, None]" [arg-type]
Found 1 error in 1 file (checked 1 source file)
Please complete the following information:
- OS: Debian 11.6
- Python: 3.9.2
- mypy: 1.1.1
- pandas: 1.5.3
- pandas-stubs: 1.5.3.230321
Additional context
#223 mentions date_range
and bdate_range
.
pandas-dev/pandas#48631 updates the documentation for date_range
, bdate_range
, and interval_range
.
#322 updates the stubs for date_range
and bdate_range
.
However, using Timedelta
or timedelta
with timedelta_range
seems to work as well. (I'm not sure I fully understand the difference between Timedelta and DateOffset, but I don't see why a Timedelta shouldn't be accepted here.)