assignment problem

[LADSoft]

I used to do something like this:

Json::Value root;
root["description"] = "this is some text";

That doesn't currently work because of a missing assignment operator. The closest thing to an assignment operator you have is:

Value &Value::operator=(Value other);

but the compiler I'm using wants

Value &Value::operator=(const Value &other);

I'm using VS2005 if that makes a difference.

[cdunn2001]

(Been traveling.)

Hmmm. VS2005 is quite old. Maybe you could try the tip of the 0.y.z branch.

[thelema]

This was broken for you by 45cd949, which switched to "copy and swap" idiom that replaces the operator=(const Value&) with an operator=(Value). Commit 8996c37 restored the operator=(const Value&) to add move assignment, but broke the copy-assignment implementation as it forgot to make the copy. This was put back to "copy and swap" in 6a15ca6 which also removed the move assignment implementation.

[cdunn2001]

See also: #37

The simplest work-around for the old compiler is to wrap the char* in Json::Value().

root["description"] = Json::Value("this is some text");

But the smartest thing is to use old versions of software with old compilers. If you cannot upgrade your compiler, you should not upgrade your libraries.

We actually have a branch which is meant to support older compilers: 0.y.z. We don't update that much, but I expect it would work for you.