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Fixed "print function's "end" option error in CPython" #92

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Fixed "print function's "end" option error in CPython" #92

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Sungmin-Joo
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@Sungmin-Joo Sungmin-Joo commented Sep 27, 2019

The following code writes different string to the stream than in CPython:

print(1,2,3, end="||\n")

I fixed that bug by modifying the code
resolved: #93

The following code writes different string to the stream than in CPython:
print(1,2,3, end="||\n")

The following code writes different string to the stream than in CPython:
print(1,2,3, end="||\n")

I fixed that bug by modifying the code
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codecov-io commented Sep 27, 2019

Codecov Report

All modified and coverable lines are covered by tests ✅

Project coverage is 69.10%. Comparing base (e427daf) to head (0d6c264).

Additional details and impacted files
@@            Coverage Diff             @@
##           master      #92      +/-   ##
==========================================
+ Coverage   69.09%   69.10%   +0.01%     
==========================================
  Files          60       60              
  Lines       10674    10678       +4     
==========================================
+ Hits         7375     7379       +4     
  Misses       2781     2781              
  Partials      518      518              

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@Sungmin-Joo Sungmin-Joo changed the title Fix "end" option in print function Fixed "print function's "end" option error in CPython" Sep 27, 2019
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@Sungmin-Joo Please add a unit test which you updated.

@corona10 corona10 requested a review from ncw September 27, 2019 06:00
add "end" test in cpython
@Sungmin-Joo
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@corona10
Is it a proper test?
If not, I will try again tomorrow.

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@Sungmin-Joo
You should show the test

AS-IS

>>> print(1,2,3, end="||\n")
1||
2||
3||

TO-BE

>>> print(1,2,3, end="||\n")
1 2 3||

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The test is not proper.

@@ -186,6 +186,12 @@ func builtin_print(self py.Object, args py.Tuple, kwargs py.StringDict) (py.Obje
if err != nil {
return nil, err
}

if kwargs["sep"] != nil {
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what about:

switch sep, ok := kwargs["sep"]; ok {
case true:
    sepObj = sep
default:
    sepObj = py.String(" ")
}

print("hello","gpython", end="123\n")
except TypeError as e:
ok = True
assert ok, "TypeError not raised"
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Suggested change
assert ok, "TypeError not raised"
assert ok, "TypeError not raised when 'sep' is not in the kwargs dict"

that said, I am not sure I understand this test.
do we really want this line to raise an exception? why?

@@ -281,6 +281,12 @@ def gen2():
ok = True
assert ok, "TypeError not raised"

try:
print("hello","gpython", end="123\n")
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Suggested change
print("hello","gpython", end="123\n")
print("hello", "gpython", end="123\n")

@corona10
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@Sungmin-Joo @sbinet
Sorry,
I think that we should fix #90 was not the proper approach.

err := py.ParseTupleAndKeywords(nil, kwargs, "|ssOO:print", kwlist, &sepObj, &endObj, &file, &flush)

I am now closing this PR
Let's fix this issue with proper approach :)

@corona10 corona10 closed this Sep 28, 2019
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print function's "end" option error in CPython
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