Add a Solution for Length of Last Word (LeetCode Problem 58)

dsa-solutions/lc-solutions/0000-0099/0058-length-of-last-word.md

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+---
+id: length-of-last-word
+title: Length of Last Word (LeetCode)
+difficulty: Easy
+sidebar_label: 0058-LengthOfLastWord
+topics:
+  - String
+---
+
+## Problem Description
+
+| Problem Statement | Solution Link | LeetCode Profile |
+| :---------------- | :------------ | :--------------- |
+| [Merge Two Sorted Lists](https://leetcode.com/problems/length-of-last-word/) | [Merge Two Sorted Lists Solution on LeetCode](https://leetcode.com/problems/length-of-last-word/solutions/) |  [VijayShankerSharma](https://leetcode.com/u/darkknight648/) |
+
+
+## Problem Description
+
+Given a string `s` consisting of words and spaces, return the length of the last word in the string.
+
+### Examples
+
+#### Example 1
+
+- **Input:** s = "Hello World"
+- **Output:** 5
+- **Explanation:** The last word is "World" with length 5.
+
+#### Example 2
+
+- **Input:** s = "   fly me   to   the moon  "
+- **Output:** 4
+- **Explanation:** The last word is "moon" with length 4.
+
+#### Example 3
+
+- **Input:** s = "luffy is still joyboy"
+- **Output:** 6
+- **Explanation:** The last word is "joyboy" with length 6.
+
+### Constraints
+
+- `1 <= s.length <= 10^4`
+- `s` consists of only English letters and spaces ' '.
+- There will be at least one word in `s`.
+
+### Approach
+
+To find the length of the last word in the string `s`, we can follow these steps:
+
+1. Trim any trailing spaces from the string.
+2. Initialize a variable `length` to store the length of the last word.
+3. Iterate over the string from right to left:
+   - When encountering a non-space character, increment `length`.
+   - Break the loop when encountering the first space character after a non-space character.
+4. Return `length`.
+
+### Solution Code
+
+#### Python
+
+```
+class Solution(object):
+    def lengthOfLastWord(self, s):
+        return len(s.split()[-1])
+```
+
+#### C++
+
+```
+class Solution {
+public:
+    int lengthOfLastWord(string s) {
+        int length = 0;
+        int n = s.length();
+        while (n > 0 && s[n - 1] == ' ') {
+            n--;  // Trim trailing spaces
+        }
+        for (int i = n - 1; i >= 0; --i) {
+            if (s[i] != ' ') {
+                length++;
+            } else if (length != 0) {
+                break;
+            }
+        }
+        return length;
+    }
+};
+```
+
+#### Java
+
+```
+class Solution {
+    public int lengthOfLastWord(String s) {
+        int length = 0;
+        s = s.trim();  // Trim trailing spaces
+        for (int i = s.length() - 1; i >= 0; --i) {
+            if (s.charAt(i) != ' ') {
+                length++;
+            } else if (length != 0) {
+                break;
+            }
+        }
+        return length;
+    }
+}
+```
+
+### Conclusion
+
+The Length of Last Word problem can be efficiently solved by trimming any trailing spaces from the string and iterating over the string from right to left to find the length of the last word. The provided solution code implements this approach in Python, C++, and Java, providing an optimal solution to the problem.