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dsa-solutions/gfg-solutions/Easy problems/Square-Root.md

@@ -1,4 +1,5 @@
 ---
+---
 id: square-root
 title: Square Root
 sidebar_label: Square-Root
@@ -190,4 +191,4 @@ class Solution {
 The provided solutions efficiently find the floor value of the square root of a given integer `x` using binary search. This approach ensures a time complexity of $ O(log N) and an auxiliary space complexity of $O(1)$. The algorithms are designed to handle large values of `x` up to 10^7 efficiently without relying on built-in square root functions.
 
 **Time Complexity:** $O(log N)$
-**Auxiliary Space:** $O(1)$
+**Auxiliary Space:** $O(1)$

dsa-solutions/lc-solutions/0000-0099/0001-two-sum.md

@@ -7,14 +7,13 @@ tags:
   - Hash Table
   - Two Pointer
   - Array
-  - LeetCode
   - JavaScript
   - TypeScript
 description: "This is a solution to the Two Sum problem on LeetCode."
 sidebar_position: 1
 ---
 
-In this tutorial, we will solve the Two Sum problem using three different approaches: brute force, hash table, and two-pointer technique. We will provide the implementation of the solution in JavaScript, TypeScript, Python, Java, C++, and more.
+In this tutorial, we will solve the Two Sum problem using three different approaches :brute force, hash table, and two-pointer technique. We will provide the implementation of the solution in JavaScript, TypeScript, Python, Java, C++, and more.
 
 ## Problem Description
 
@@ -441,28 +440,28 @@ function twoSumProblem() {
   <TabItem value="TypeScript" label="TypeScript">
   <SolutionAuthor name="@ajay-dhangar"/>
 
- ```ts
- function twoSum(nums: number[], target: number): number[] {
-   const sortedNums = nums.map((num, index) => [num, index]);
-   sortedNums.sort((a, b) => a[0] - b[0]);
-
-   let left = 0;
-   let right = sortedNums.length - 1;
-
-   while (left < right) {
-     const sum = sortedNums[left][0] + sortedNums[right][0];
-     if (sum === target) {
-       return [sortedNums[left][1], sortedNums[right][1]];
-     } else if (sum < target) {
-       left++;
-     } else {
-       right--;
-     }
-   }
+```ts
+function twoSum(nums: number[], target: number): number[] {
+  const sortedNums = nums.map((num, index) => [num, index]);
+  sortedNums.sort((a, b) => a[0] - b[0]);
+
+  let left = 0;
+  let right = sortedNums.length - 1;
+
+  while (left < right) {
+    const sum = sortedNums[left][0] + sortedNums[right][0];
+    if (sum === target) {
+      return [sortedNums[left][1], sortedNums[right][1]];
+    } else if (sum < target) {
+      left++;
+    } else {
+      right--;
+    }
+  }
 
-   return [];
- }
- ```
+  return [];
+}
+```
 
 </TabItem>
 <TabItem value="Python" label="Python">
@@ -484,39 +483,40 @@ function twoSumProblem() {
              right -= 1
 
      return []
- ```
+
+````
 
 </TabItem>
 <TabItem value="Java" label="Java">
 <SolutionAuthor name="@ajay-dhangar"/>
 ```java
- class Solution {
-     public int[] twoSum(int[] nums, int target) {
-         int[][] sortedNums = new int[nums.length][2];
-         for (int i = 0; i < nums.length; i++) {
-             sortedNums[i] = new int[] {nums[i], i};
-         }
+class Solution {
+    public int[] twoSum(int[] nums, int target) {
+        int[][] sortedNums = new int[nums.length][2];
+        for (int i = 0; i < nums.length; i++) {
+            sortedNums[i] = new int[] {nums[i], i};
+        }
 
-         Arrays.sort(sortedNums, (a, b) -> Integer.compare(a[0], b[0]));
+        Arrays.sort(sortedNums, (a, b) -> Integer.compare(a[0], b[0]));
 
-         int left = 0;
-         int right = sortedNums.length - 1;
+        int left = 0;
+        int right = sortedNums.length - 1;
 
-         while (left < right) {
-             int sum = sortedNums[left][0] + sortedNums[right][0];
-             if (sum == target) {
-                 return new int[] {sortedNums[left][1], sortedNums[right][1]};
-             } else if (sum < target) {
-                 left++;
-             } else {
-                 right--;
-             }
-         }
+        while (left < right) {
+            int sum = sortedNums[left][0] + sortedNums[right][0];
+            if (sum == target) {
+                return new int[] {sortedNums[left][1], sortedNums[right][1]};
+            } else if (sum < target) {
+                left++;
+            } else {
+                right--;
+            }
+        }
 
-         return new int[0];
-     }
- }
- ```
+        return new int[0];
+    }
+}
+````
 
 </TabItem>
 <TabItem value="C++" label="C++">
@@ -552,7 +552,7 @@ function twoSumProblem() {
          return {};
      }
  };
- ```
+```
 
 </TabItem>
 </Tabs>
@@ -585,16 +585,16 @@ The hash table approach is the most efficient and is recommended for large input
 
   <TabItem value="en" label="English">
 
-  ---
-  
+---
+
     <Tabs>
       <TabItem value="javascript" label="JavaScript">
         <LiteYouTubeEmbed
           id="mK1_vjxMfh4"
           params="autoplay=1&autohide=1&showinfo=0&rel=0"
           title="Two Sum Problem Explanation | Two Sum Problem Solution | Two Sum Problem Approach"
           poster="maxresdefault"
-          webp 
+          webp
         />
       </TabItem>
 
@@ -604,7 +604,7 @@ The hash table approach is the most efficient and is recommended for large input
           params="autoplay=1&autohide=1&showinfo=0&rel=0"
           title="Two Sum Problem Explanation | Two Sum Problem Solution | Two Sum Problem Approach"
           poster="maxresdefault"
-          webp 
+          webp
         />
       </TabItem>
       <TabItem value="java" label="Java">
@@ -613,7 +613,7 @@ The hash table approach is the most efficient and is recommended for large input
           params="autoplay=1&autohide=1&showinfo=0&rel=0"
           title="Two Sum Problem Explanation | Two Sum Problem Solution | Two Sum Problem Approach"
           poster="maxresdefault"
-          webp 
+          webp
         />
       </TabItem>
     </Tabs>
@@ -640,4 +640,4 @@ The hash table approach is the most efficient and is recommended for large input
 {['ajay-dhangar'].map(username => (
  <Author key={username} username={username} />
 ))}
-</div>
+</div>

dsa-solutions/lc-solutions/0100-0199/0138-Copy-List-with-Random-Pointer.md

@@ -6,8 +6,7 @@ tags:
   - Java
   - Python
   - C++
-  - JavaScript
-
+  - JavaScript  
 description: "This is a solution to the Copy List with Random Pointer problem on LeetCode."
 ---
 
@@ -37,13 +36,16 @@ Output: [[7,null],[13,0],[11,4],[10,2],[1,0]]
 ```
 Input: head = [[1,1],[2,1]]
 Output: [[1,1],[2,1]]
-
 ```
 
----
+### Constraints:
 
-## Solution for Copy List with Random Pointer
+- The number of nodes in the list is in the range [0, 1000].
+- `-10000 <= Node.val <= 10000`
+- Node.random is null or is pointing to some node in the linked list.
+---
 
+##  Approach to Solve the Copy List with Random Pointer Problem
 
 ### Understand the Problem:
 

dsa-solutions/lc-solutions/0900-0999/0906-super-palindromes.md

@@ -2,15 +2,15 @@
 id: super-palindromes
 title: Super Palindromes
 sidebar_label: Super Palindromes
-tags: 
-    - Palindrome
-    - Math
+tags:
+  - Palindrome
+  - Math
 ---
 
 ## Problem Description
 
-| Problem Statement                                       | Solution Link                                                              | LeetCode Profile                                        |
-| :------------------------------------------------------ | :------------------------------------------------------------------------- | :------------------------------------------------------ |
+| Problem Statement                                                                 | Solution Link                                                                                        | LeetCode Profile                                     |
+| :-------------------------------------------------------------------------------- | :--------------------------------------------------------------------------------------------------- | :--------------------------------------------------- |
 | [Super Palindromes](https://leetcode.com/problems/super-palindromes/description/) | [Super Palindromes Solution on LeetCode](https://leetcode.com/problems/super-palindromes/solutions/) | [Nikita Saini](https://leetcode.com/u/Saini_Nikita/) |
 
 ## Problem Description
@@ -62,7 +62,7 @@ def super_palindromes(left, right):
     left, right = int(left), int(right)
     count = 0
     limit = int(math.sqrt(right)) + 1
-    
+
     for i in range(1, limit):
         s = str(i)
         pal = s + s[::-1]
@@ -71,14 +71,14 @@ def super_palindromes(left, right):
             break
         if num >= left and is_palindrome(str(num)):
             count += 1
-        
+
         pal = s + s[-2::-1]
         num = int(pal) ** 2
         if num > right:
             break
         if num >= left and is_palindrome(str(num)):
             count += 1
-    
+
     return count
 ```
 
@@ -178,7 +178,7 @@ int superPalindromes(char* left, char* right) {
     for (long long i = 1; i < limit; i++) {
         sprintf(s, "%lld", i);
         int len = strlen(s);
-        
+
         // Palindrome of even length
         snprintf(pal, 40, "%s%s", s, strrev(strdup(s)));
         long long num1 = atoll(pal) * atoll(pal);
@@ -200,28 +200,29 @@ int superPalindromes(char* left, char* right) {
 
 ```javascript
 function isPalindrome(s) {
-    return s === s.split('').reverse().join('');
+  return s === s.split("").reverse().join("");
 }
 
 function superPalindromes(left, right) {
-    let l = BigInt(left), r = BigInt(right);
-    let count = 0;
-    let limit = BigInt(Math.sqrt(Number(r))) + BigInt(1);
-
-    for (let i = BigInt(1); i < limit; i++) {
-        let s = i.toString();
-        let pal1 = s + s.split('').reverse().join('');
-        let num1 = BigInt(pal1) ** BigInt(2);
-        if (num1 > r) break;
-        if (num1 >= l && isPalindrome(num1.toString())) count++;
-
-        let pal2 = s + s.slice(0, -1).split('').reverse().join('');
-        let num2 = BigInt(pal2) ** BigInt(2);
-        if (num2 > r) break;
-        if (num2 >= l && isPalindrome(num2.toString())) count++;
-    }
-
-    return count;
+  let l = BigInt(left),
+    r = BigInt(right);
+  let count = 0;
+  let limit = BigInt(Math.sqrt(Number(r))) + BigInt(1);
+
+  for (let i = BigInt(1); i < limit; i++) {
+    let s = i.toString();
+    let pal1 = s + s.split("").reverse().join("");
+    let num1 = BigInt(pal1) ** BigInt(2);
+    if (num1 > r) break;
+    if (num1 >= l && isPalindrome(num1.toString())) count++;
+
+    let pal2 = s + s.slice(0, -1).split("").reverse().join("");
+    let num2 = BigInt(pal2) ** BigInt(2);
+    if (num2 > r) break;
+    if (num2 >= l && isPalindrome(num2.toString())) count++;
+  }
+
+  return count;
 }
 ```
 
@@ -230,12 +231,13 @@ function superPalindromes(left, right) {
 1. **Generate Palindromes:**
    - Iterate through possible values of `i` from 1 to the square root of the right boundary.
    - Construct palindromes by concatenating `s` with its reverse and with its reverse minus the last character.
-
 2. **Square Palindromes:**
+
    - Compute the square of each palindrome.
    - Check if the squared value is within the range `[left, right]`.
 
 3. **Check for Super-Palindromes:**
+
    - Verify if the squared palindrome is also a palindrome.
 
 4. **Count and Return:**