|
| 1 | +--- |
| 2 | +id: Find the Difference |
| 3 | +title: Find the Difference |
| 4 | +sidebar_label: 0389-Find the Difference |
| 5 | +tags: |
| 6 | + - Leet code |
| 7 | +description: "Solution to leetocde 389" |
| 8 | +--- |
| 9 | + |
| 10 | +### Problem Description |
| 11 | + |
| 12 | +You are given two strings s and t. |
| 13 | + |
| 14 | +String t is generated by random shuffling string s and then add one more letter at a random position. |
| 15 | + |
| 16 | +Return the letter that was added to t. |
| 17 | + |
| 18 | +Example 1: |
| 19 | + |
| 20 | +``` |
| 21 | +Input: s = "abcd", t = "abcde" |
| 22 | +Output: "e" |
| 23 | +Explanation: 'e' is the letter that was added. |
| 24 | +``` |
| 25 | + |
| 26 | +Example 2: |
| 27 | + |
| 28 | +``` |
| 29 | +Input: s = "", t = "y" |
| 30 | +Output: "y" |
| 31 | +``` |
| 32 | + |
| 33 | +### Constraints: |
| 34 | + |
| 35 | +- $0 <= s.length <= 1000$ |
| 36 | +- $t.length == s.length + 1$ |
| 37 | +- $s and t consist of lowercase English letters.$ |
| 38 | + |
| 39 | +### Algorithm |
| 40 | + |
| 41 | +1. For each character i in t, it checks if the count of i in t is greater than the count of i in s. If this condition is met, it means that i is the extra letter that was added to t, so it returns i and breaks out of the loop. |
| 42 | + |
| 43 | +### Code Implementation |
| 44 | + |
| 45 | +**Python:** |
| 46 | + |
| 47 | +```python |
| 48 | +class Solution(object): |
| 49 | + def findTheDifference(self, s, t): |
| 50 | + for char in t: |
| 51 | + if t.count(char) > s.count(char): |
| 52 | + return char |
| 53 | +``` |
| 54 | + |
| 55 | +**C++:** |
| 56 | + |
| 57 | +```c++ |
| 58 | +#include <unordered_map> |
| 59 | + |
| 60 | +char findTheDifference(std::string s, std::string t) { |
| 61 | + std::unordered_map<char, int> char_counts; |
| 62 | + for (char c : s) { |
| 63 | + char_counts[c]++; |
| 64 | + } |
| 65 | + for (char c : t) { |
| 66 | + if (char_counts.find(c) == char_counts.end() || char_counts[c] == 0) { |
| 67 | + return c; |
| 68 | + } |
| 69 | + char_counts[c]--; |
| 70 | + } |
| 71 | + return '\0'; // Return null character if no difference found |
| 72 | +} |
| 73 | +``` |
| 74 | +
|
| 75 | +**Java:** |
| 76 | +
|
| 77 | +```java |
| 78 | +public class Solution { |
| 79 | + public char findTheDifference(String s, String t) { |
| 80 | + HashMap<Character, Integer> char_counts = new HashMap<>(); |
| 81 | + for (char c : s.toCharArray()) { |
| 82 | + char_counts.put(c, char_counts.getOrDefault(c, 0) + 1); |
| 83 | + } |
| 84 | + for (char c : t.toCharArray()) { |
| 85 | + if (!char_counts.containsKey(c) || char_counts.get(c) == 0) { |
| 86 | + return c; |
| 87 | + } |
| 88 | + char_counts.put(c, char_counts.get(c) - 1); |
| 89 | + } |
| 90 | + return '\u0000'; // Return null character if no difference found (Unicode representation) |
| 91 | + } |
| 92 | +} |
| 93 | +``` |
| 94 | + |
| 95 | +**JavaScript:** |
| 96 | + |
| 97 | +```javascript |
| 98 | +function findTheDifference(s, t) { |
| 99 | + const char_counts = {}; |
| 100 | + for (const char of s) { |
| 101 | + char_counts[char] = (char_counts[char] || 0) + 1; |
| 102 | + } |
| 103 | + for (const char of t) { |
| 104 | + if (!(char in char_counts) || char_counts[char] === 0) { |
| 105 | + return char; |
| 106 | + } |
| 107 | + char_counts[char]--; |
| 108 | + } |
| 109 | + return ""; // Return empty string if no difference found |
| 110 | +} |
| 111 | +``` |
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