|
| 1 | +--- |
| 2 | +id: ransome-note |
| 3 | +title: Ransom Note |
| 4 | +sidebar_label: 0383-Ransom Note |
| 5 | +tags: |
| 6 | + - Leet code |
| 7 | +description: "Solution to leetocde 383" |
| 8 | +--- |
| 9 | + |
| 10 | +### Problem Description |
| 11 | + |
| 12 | +Given two strings ransomNote and magazine, return true if ransomNote can be constructed by using the letters from magazine and false otherwise. |
| 13 | + |
| 14 | +Each letter in magazine can only be used once in ransomNote. |
| 15 | + |
| 16 | +### Examples |
| 17 | + |
| 18 | +Example 1: |
| 19 | + |
| 20 | +``` |
| 21 | +Input: ransomNote = "a", magazine = "b" |
| 22 | +Output: false |
| 23 | +``` |
| 24 | + |
| 25 | +Example 2: |
| 26 | + |
| 27 | +``` |
| 28 | +Input: ransomNote = "aa", magazine = "ab" |
| 29 | +Output: false |
| 30 | +``` |
| 31 | + |
| 32 | +Example 3: |
| 33 | + |
| 34 | +``` |
| 35 | +Input: ransomNote = "aa", magazine = "aab" |
| 36 | +Output: true |
| 37 | +``` |
| 38 | + |
| 39 | +### Constraints: |
| 40 | + |
| 41 | +- $1 <= ransomNote.length, magazine.length <= 10^5$ |
| 42 | +- ransomNote and magazine consist of lowercase English letters. |
| 43 | + Alright, here's the breakdown of the code you provided, along with implementations in various languages: |
| 44 | + |
| 45 | +### Algorithm: |
| 46 | + |
| 47 | +1. **Initialize a frequency table:** The code creates an array `alpha` of size 26. This array will store the frequency of each letter in the magazine (`a` maps to index 0, `b` to index 1, and so on). |
| 48 | +2. **Iterate through ransom note:** For each character `c` in the ransom note: |
| 49 | + - Calculate the index `idx` using `ord(c) - ord('a')`. This converts the character `c` to its corresponding numerical position (e.g., 'a' becomes 0, 'b' becomes 1). |
| 50 | + - Use `magazine.find(c, alpha[idx])` to find the first occurrence of `c` in the magazine starting from index `alpha[idx]`. This improves efficiency by avoiding redundant searches in the magazine. |
| 51 | + - If `i` (the result of `find`) is -1, it means the character `c` is not found in the magazine. In this case, the function returns `False` as the ransom note cannot be formed. |
| 52 | + - Update `alpha[idx]` with `i + 1` to track the last position where `c` was found in the magazine. This helps avoid revisiting the same characters in the magazine unnecessarily. |
| 53 | +3. **Return True:** After iterating through the entire ransom note, if no characters were missing, the function returns `True`, indicating that the ransom note can be constructed from the magazine. |
| 54 | + |
| 55 | +**Code Implementations:** |
| 56 | + |
| 57 | +**Python:** |
| 58 | + |
| 59 | +```python |
| 60 | +from collections import Counter |
| 61 | + |
| 62 | +class Solution: |
| 63 | + def canConstruct(self, ransomNote: str, magazine: str) -> bool: |
| 64 | + magazine_counter = Counter(magazine) |
| 65 | + ransom_counter = Counter(ransomNote) |
| 66 | + for char, count in ransom_counter.items(): |
| 67 | + if char not in magazine_counter or magazine_counter[char] < count: |
| 68 | + return False |
| 69 | + return True |
| 70 | +``` |
| 71 | + |
| 72 | +**C++:** |
| 73 | + |
| 74 | +```c++ |
| 75 | +#include <unordered_map> |
| 76 | + |
| 77 | +class Solution { |
| 78 | +public: |
| 79 | + bool canConstruct(std::string ransomNote, std::string magazine) { |
| 80 | + std::unordered_map<char, int> magazine_counter; |
| 81 | + for (char c : magazine) { |
| 82 | + magazine_counter[c]++; |
| 83 | + } |
| 84 | + for (char c : ransomNote) { |
| 85 | + if (magazine_counter.find(c) == magazine_counter.end() || magazine_counter[c] == 0) { |
| 86 | + return false; |
| 87 | + } |
| 88 | + magazine_counter[c]--; |
| 89 | + } |
| 90 | + return true; |
| 91 | + } |
| 92 | +}; |
| 93 | +``` |
| 94 | +
|
| 95 | +**Java:** |
| 96 | +
|
| 97 | +```java |
| 98 | +import java.util.HashMap; |
| 99 | +
|
| 100 | +class Solution { |
| 101 | + public boolean canConstruct(String ransomNote, String magazine) { |
| 102 | + HashMap<Character, Integer> magazine_counter = new HashMap<>(); |
| 103 | + for (char c : magazine.toCharArray()) { |
| 104 | + magazine_counter.put(c, magazine_counter.getOrDefault(c, 0) + 1); |
| 105 | + } |
| 106 | + for (char c : ransomNote.toCharArray()) { |
| 107 | + if (!magazine_counter.containsKey(c) || magazine_counter.get(c) == 0) { |
| 108 | + return false; |
| 109 | + } |
| 110 | + magazine_counter.put(c, magazine_counter.get(c) - 1); |
| 111 | + } |
| 112 | + return true; |
| 113 | + } |
| 114 | +} |
| 115 | +``` |
| 116 | + |
| 117 | +**JavaScript:** |
| 118 | + |
| 119 | +```javascript |
| 120 | +function canConstruct(ransomNote, magazine) { |
| 121 | + const magazine_counter = {}; |
| 122 | + for (const char of magazine) { |
| 123 | + magazine_counter[char] = (magazine_counter[char] || 0) + 1; |
| 124 | + } |
| 125 | + for (const char of ransomNote) { |
| 126 | + if (!(char in magazine_counter) || magazine_counter[char] === 0) { |
| 127 | + return false; |
| 128 | + } |
| 129 | + magazine_counter[char]--; |
| 130 | + } |
| 131 | + return true; |
| 132 | +} |
| 133 | +``` |
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