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JavaScript Merge Sort Algorithm
Ramesh Fadatare edited this page Jul 11, 2019
·
1 revision
function merge(left, right, compareFn) {
let i = 0;
let j = 0;
const result = [];
while (i < left.length && j < right.length) {
result.push(compareFn(left[i], right[j]) === Compare.LESS_THAN ? left[i++] : right[j++]);
}
return result.concat(i < left.length ? left.slice(i) : right.slice(j));
}
function mergeSort(array, compareFn = defaultCompare) {
if (array.length > 1) {
const { length } = array;
const middle = Math.floor(length / 2);
const left = mergeSort(array.slice(0, middle), compareFn);
const right = mergeSort(array.slice(middle, length), compareFn);
array = merge(left, right, compareFn);
}
return array;
}
const Compare = {
LESS_THAN: -1,
BIGGER_THAN: 1,
EQUALS: 0
};
function defaultCompare(a, b) {
if (a === b) {
return Compare.EQUALS;
}
return a < b ? Compare.LESS_THAN : Compare.BIGGER_THAN;
}
let array = [2,1,5,4,3,8,7,6];
array = mergeSort(array);
console.log(array);
Output:
[1, 2, 3, 4, 5, 6, 7, 8]