Removing logging.

Author: James Cori

src/controllers/syncController.js

@@ -75,18 +75,18 @@ async function queueChallenges (filter) {
   let running = true
   let queuedCount = 0
 
-  logger.debug(`Filter: ${JSON.stringify(filter)}`)
+  // logger.debug(`Filter: ${JSON.stringify(filter)}`)
   // get active challenges from v4
   const v4response = await syncService.getV4ChallengeIds(filter)
-  logger.debug(`v4 Response: ${JSON.stringify(v4response)}`)
+  // logger.debug(`v4 Response: ${JSON.stringify(v4response)}`)
   const v4IdArray = _.map(_.get(v4response, 'ids', []), id => _.toNumber(id))
   // console.log('v4', v4IdArray)
-  logger.debug(`v4 Array ${JSON.stringify(v4IdArray)}`)
+  // logger.debug(`v4 Array ${JSON.stringify(v4IdArray)}`)
   // get active challenges from v5
   const v5response = await syncService.getV5LegacyChallengeIds(filter)
-  logger.debug(`v5 Response: ${JSON.stringify(v5response)}`)
+  // logger.debug(`v5 Response: ${JSON.stringify(v5response)}`)
   const v5IdArray = _.map(_.get(v5response, 'ids', []), id => _.toNumber(id))
-  logger.debug(`v5 Array ${JSON.stringify(v5IdArray)}`)
+  // logger.debug(`v5 Array ${JSON.stringify(v5IdArray)}`)
 
   // combine arrays, return unique
   const combinedArray = union(v4IdArray, v5IdArray)
@@ -127,13 +127,13 @@ async function queueChallengeById (legacyId, withLogging = false, force = false)
     logger.info(`Sync :: Queue challenge with ID: ${legacyId}`)
   }
 
-  logger.debug(`queueChallengeById - Force Value: ${force} - Force Check: ${force === true}`)
+  // logger.debug(`queueChallengeById - Force Value: ${force} - Force Check: ${force === true}`)
   if (force === true) {
     // forced, do it anyway
     logger.info(`Sync :: Sync of ${legacyId} is being forced`)
     return challengeSyncStatusService.queueForSync(legacyId, true)
-  } else {
-    logger.debug(`Sync :: Sync Not Forced ${legacyId}`)
+  // } else {
+    // logger.debug(`Sync :: Sync Not Forced ${legacyId}`)
   }
 
   // make sure it's not already queued