Fix the Symbol.newClass example

Author: Kordyjan

blog/_posts/2022-06-15-scala-3.1.3-released.md

@@ -72,7 +72,7 @@ import scala.quoted.*
 
 class Base
 
-transparent inline def classNamed(inline name: String) = new Base
+transparent inline def classNamed(inline name: String) = ${ classNamedExpr('name) }
 def classNamedExpr(nameExpr: Expr[String])(using Quotes): Expr[Any] =
   import quotes.reflect.*
 
@@ -92,7 +92,7 @@ def classNamedExpr(nameExpr: Expr[String])(using Quotes): Expr[Any] =
 Then you can invoke the macro with
 
 ```scala
-val impl: Base = scope.classNamed("Foo")
+val impl: Base = classNamed("Foo")
 ```
 
 creating the new instance of your custom subclass of `Base`. That can be useful for the compile-time generation of proxies for remote procedure call systems and many other advanced use-cases.