---

yaml
---
r: 275006
b: refs/heads/stable
c: 1536195
h: refs/heads/master

Author: sandeep-datta

[refs]

@@ -29,7 +29,7 @@ refs/heads/tmp: e06d2ad9fcd5027bcaac5b08fc9aa39a49d0ecd3
 refs/tags/1.0.0-alpha.2: 4c705f6bc559886632d3871b04f58aab093bfa2f
 refs/tags/homu-tmp: c0221c8897db309a79990367476177b1230bb264
 refs/tags/1.0.0-beta: 8cbb92b53468ee2b0c2d3eeb8567005953d40828
-refs/heads/stable: 37a952a672ca79bfcc41795e378a710c196a557a
+refs/heads/stable: 1536195ce66dcf764782e1f36ced4aa5eefef321
 refs/tags/1.0.0: 55bd4f8ff2b323f317ae89e254ce87162d52a375
 refs/tags/1.1.0: bc3c16f09287e5545c1d3f76b7abd54f2eca868b
 refs/tags/1.2.0: f557861f822c34f07270347b94b5280de20a597e

branches/stable/src/doc/book/ownership.md

@@ -139,7 +139,7 @@ Now consider the following code fragment:
 ```rust
 let v = vec![1, 2, 3];
 
-let v2 = v;
+let mut v2 = v;
 ```
 
 The first line allocates memory for the vector object `v` on the stack like
@@ -167,7 +167,7 @@ For example if we truncated the vector to just two elements through `v2`:
 
 ```rust
 # let v = vec![1, 2, 3];
-# let v2 = v;
+# let mut v2 = v;
 v2.truncate(2);
 ```