Further remove the "default" representation

This updates some more references to the "default" representation and
instead refers to it directly as the "Rust" representation. This is
intended to more consistently refer to the same concept.

Author: ehuss

src/items/enumerations.md

@@ -111,7 +111,7 @@ let z = StructLike { value: 123 }; // Struct expression.
 Each enum instance has a _discriminant_: an integer logically associated to it
 that is used to determine which variant it holds.
 
-Under the [default representation], the discriminant is interpreted as
+Under the [`Rust` representation], the discriminant is interpreted as
 an `isize` value. However, the compiler is allowed to use a smaller type (or
 another means of distinguishing variants) in its actual memory layout.
 
@@ -333,14 +333,14 @@ enum E {
 [`C` representation]: ../type-layout.md#the-c-representation
 [call expression]: ../expressions/call-expr.md
 [constant expression]: ../const_eval.md#constant-expressions
-[default representation]: ../type-layout.md#the-default-representation
 [enumerated type]: ../types/enum.md
 [Field-less enums]: #field-less-enum
 [IDENTIFIER]: ../identifiers.md
 [never type]: ../types/never.md
 [numeric cast]: ../expressions/operator-expr.md#semantics
 [path expression]: ../expressions/path-expr.md
 [primitive representation]: ../type-layout.md#primitive-representations
+[`Rust` representation]: ../type-layout.md#the-rust-representation
 [struct expression]: ../expressions/struct-expr.md
 [struct]: structs.md
 [type namespace]: ../names/namespaces.md

src/type-layout.md

@@ -204,7 +204,7 @@ struct AlignedStruct {
 r[layout.repr.inter-field]
 The representation of a type can change the padding between fields, but does
 not change the layout of the fields themselves. For example, a struct with a
-`C` representation that contains a struct `Inner` with the default
+`C` representation that contains a struct `Inner` with the `Rust`
 representation will not change the layout of `Inner`.
 
 <a id="the-default-representation"></a>