Improved tasks 175-184

Author: javadev

src/main/java/g0101_0200/s0175_combine_two_tables/script.sql

@@ -1,4 +1,12 @@
 # Write your MySQL query statement below
 # #Easy #Database #SQL_I_Day_5_Union #2022_06_26_Time_491_ms_(32.30%)_Space_0B_(100.00%)
-SELECT FirstName, LastName, City, State
-FROM Person LEFT JOIN Address USING (PersonId)
+SELECT 
+    FirstName, 
+    LastName, 
+    City, 
+    State
+FROM 
+    Person
+LEFT JOIN 
+    Address
+USING (PersonId);

src/main/java/g0101_0200/s0176_second_highest_salary/script.sql

@@ -1,9 +1,13 @@
 # Write your MySQL query statement below
 # #Medium #Database #SQL_I_Day_4_Union_and_Select
 # #2022_07_10_Time_225_ms_(73.10%)_Space_0B_(100.00%)
-SELECT ifnull(
-                (SELECT distinct(Salary)
-                 FROM Employee
-                 ORDER BY Salary DESC
-                 LIMIT 1
-                 OFFSET 1), NULL) SecondHighestSalary;
+SELECT
+    IFNULL(
+        (
+            SELECT DISTINCT Salary
+            FROM Employee
+            ORDER BY Salary DESC
+            LIMIT 1 OFFSET 1
+        ),
+        NULL
+    ) AS SecondHighestSalary;

src/main/java/g0101_0200/s0178_rank_scores/script.sql

@@ -1,3 +1,10 @@
 # Write your MySQL query statement below
 # #Medium #Database #2022_06_26_Time_290_ms_(66.73%)_Space_0B_(100.00%)
-select Score, DENSE_RANK() OVER(order by Score Desc) as "Rank" from Scores order by "Rank" Asc;
+SELECT
+    Score,
+    DENSE_RANK() OVER (ORDER BY Score DESC) AS Rank
+FROM
+    Scores
+ORDER BY
+    Rank ASC;
+

src/main/java/g0101_0200/s0180_consecutive_numbers/script.sql

@@ -1,7 +1,11 @@
 # Write your MySQL query statement below
 # #Medium #Database #2024_07_15_Time_469_ms_(89.19%)_Space_0B_(100.00%)
-SELECT DISTINCT l1.num AS ConsecutiveNums
-FROM Logs l1
-JOIN Logs l2 ON l1.id = l2.id - 1
-JOIN Logs l3 ON l1.id = l3.id - 2
-WHERE l1.num = l2.num AND l2.num = l3.num;
+SELECT DISTINCT
+    l1.num AS ConsecutiveNums
+FROM
+    Logs l1
+    JOIN Logs l2 ON l1.id = l2.id - 1
+    JOIN Logs l3 ON l1.id = l3.id - 2
+WHERE
+    l1.num = l2.num
+    AND l2.num = l3.num;

src/main/java/g0101_0200/s0181_employees_earning_more_than_their_managers/script.sql

@@ -1,4 +1,10 @@
 # Write your MySQL query statement below
 # #Easy #Database #2022_06_27_Time_315_ms_(94.44%)_Space_0B_(100.00%)
-select a.Name as Employee from Employee a left join Employee b on a.ManagerId=b.Id
-where a.Salary > b.Salary and a.ManagerId is not null
+SELECT
+    a.Name AS Employee
+FROM
+    Employee a
+    LEFT JOIN Employee b ON a.ManagerId = b.Id
+WHERE
+    a.Salary > b.Salary
+    AND a.ManagerId IS NOT NULL;

src/main/java/g0101_0200/s0182_duplicate_emails/script.sql

@@ -1,3 +1,11 @@
 # Write your MySQL query statement below
 # #Easy #Database #SQL_I_Day_10_Where #2022_06_27_Time_303_ms_(92.08%)_Space_0B_(100.00%)
-SELECT Email FROM Person GROUP BY Email HAVING COUNT(Email) > 1;
+SELECT
+    Email
+FROM
+    Person
+GROUP BY
+    Email
+HAVING
+    COUNT(Email) > 1;
+

src/main/java/g0101_0200/s0183_customers_who_never_order/script.sql

@@ -1,7 +1,9 @@
 # Write your MySQL query statement below
 # #Easy #Database #SQL_I_Day_1_Select #2022_06_27_Time_376_ms_(98.73%)_Space_0B_(100.00%)
-SELECT c.Name as Customers 
-FROM Customers as c
-LEFT JOIN Orders as o
-ON c.Id = o.CustomerId  
-WHERE o.CustomerId is null
+SELECT
+    c.Name AS Customers
+FROM
+    Customers AS c
+    LEFT JOIN Orders AS o ON c.Id = o.CustomerId
+WHERE
+    o.CustomerId IS NULL;

src/main/java/g0101_0200/s0184_department_highest_salary/script.sql

@@ -5,13 +5,18 @@ SELECT
     Sel.Name AS Employee,
     Sel.Salary AS Salary
 FROM
-(
-    SELECT
-        Name,
-        Salary,
-        DepartmentId,
-        DENSE_RANK() OVER (PARTITION BY DepartmentId ORDER BY Salary DESC) AS dr
-    FROM Employee 
-) AS Sel
-INNER JOIN Department d ON d.Id = Sel.DepartmentId
-WHERE Sel.dr = 1
+    (
+        SELECT
+            Name,
+            Salary,
+            DepartmentId,
+            DENSE_RANK() OVER (
+                PARTITION BY DepartmentId
+                ORDER BY Salary DESC
+            ) AS dr
+        FROM
+            Employee
+    ) AS Sel
+    INNER JOIN Department d ON d.Id = Sel.DepartmentId
+WHERE
+    Sel.dr = 1;