diff --git a/1075. Project Employees I.sql b/1075. Project Employees I.sql
index 385a71d..21555c6 100644
--- a/1075. Project Employees I.sql	
+++ b/1075. Project Employees I.sql	
@@ -71,7 +71,6 @@ Output:
 Explanation: The average experience years for the first project is (3 + 2 + 1) / 3 = 2.00 and for the second project is (3 + 2) / 2 = 2.50
 
 '''SQL
-
 # Write your MySQL query statement below
 select project_id , round(avg(experience_years), 2) as average_years
 from project as p
@@ -79,4 +78,4 @@ left join employee as e
 on p.employee_id = e.employee_id
 group by project_id;
 
-'''
\ No newline at end of file
+'''