added 3131 solution lc

Author: VaishnaviMankala19

dsa-solutions/lc-solutions/3100-3199/3131-Find-The-Integer-Added-To-Array-1

@@ -0,0 +1,129 @@
+---
+id: find-integer-added-to-array
+title: Find the Integer Added to Array I (LeetCode)
+sidebar_label: 3131-FindIntegerAddedToArray
+tags:
+  - Array
+  - Math
+description: Given two arrays of equal length, nums1 and nums2, find the integer that has been added to each element of nums1 to obtain nums2.
+sidebar_position: 3131
+---
+
+## Problem Description
+
+| Problem Statement | Solution Link | LeetCode Profile |
+| :---------------- | :------------ | :--------------- |
+| [Find the Integer Added to Array I](https://leetcode.com/problems/find-the-integer-added-to-array-i/) | [Find the Integer Added to Array I Solution on LeetCode](https://leetcode.com/problems/find-the-integer-added-to-array-i/solutions/) | [vaishu_1904](https://leetcode.com/u/vaishu_1904/) |
+
+## Problem Description
+
+You are given two arrays of equal length, `nums1` and `nums2`.
+
+Each element in `nums1` has been increased (or decreased in the case of negative) by an integer, represented by the variable `x`.
+
+As a result, `nums1` becomes equal to `nums2`. Two arrays are considered equal when they contain the same integers with the same frequencies.
+
+Return the integer `x`.
+
+### Example 1
+
+- **Input:** `nums1 = [2, 6, 4], nums2 = [9, 7, 5]`
+- **Output:** `3`
+- **Explanation:** The integer added to each element of `nums1` is `3`.
+
+### Example 2
+
+- **Input:** `nums1 = [10], nums2 = [5]`
+- **Output:** `-5`
+- **Explanation:** The integer added to each element of `nums1` is `-5`.
+
+### Example 3
+
+- **Input:** `nums1 = [1, 1, 1, 1], nums2 = [1, 1, 1, 1]`
+- **Output:** `0`
+- **Explanation:** The integer added to each element of `nums1` is `0`.
+
+### Constraints
+
+- `1 <= nums1.length == nums2.length <= 100`
+- `0 <= nums1[i], nums2[i] <= 1000`
+- The test cases are generated in a way that there is an integer `x` such that `nums1` can become equal to `nums2` by adding `x` to each element of `nums1`.
+
+## Approach
+
+To find the integer `x` that was added to each element of `nums1` to obtain `nums2`, we can use the following approach:
+
+1. Iterate through the arrays `nums1` and `nums2`.
+2. Calculate the difference `x` for the first pair of elements from `nums1` and `nums2`.
+3. Ensure that the calculated `x` is consistent for all elements.
+
+### Solution Code
+
+#### Python
+
+```python
+def find_integer_added_to_array(nums1, nums2):
+    if len(nums1) != len(nums2):
+        return None  # Inconsistent input lengths
+    
+    x = nums2[0] - nums1[0]
+    
+    for i in range(1, len(nums1)):
+        if nums2[i] - nums1[i] != x:
+            return None  # Inconsistent difference found
+    
+    return x
+```
+
+#### C++
+
+```c++
+#include <vector>
+#include <iostream>
+using namespace std;
+
+class Solution {
+public:
+    int findIntegerAddedToArray(vector<int>& nums1, vector<int>& nums2) {
+        if (nums1.size() != nums2.size()) {
+            return INT_MIN;  // Inconsistent input lengths
+        }
+        
+        int x = nums2[0] - nums1[0];
+        
+        for (size_t i = 1; i < nums1.size(); ++i) {
+            if (nums2[i] - nums1[i] != x) {
+                return INT_MIN;  // Inconsistent difference found
+            }
+        }
+        
+        return x;
+    }
+};
+
+```
+
+#### Java
+
+```java
+class Solution {
+    public Integer findIntegerAddedToArray(int[] nums1, int[] nums2) {
+        if (nums1.length != nums2.length) {
+            return null;  // Inconsistent input lengths
+        }
+        
+        int x = nums2[0] - nums1[0];
+        
+        for (int i = 1; i < nums1.length; i++) {
+            if (nums2[i] - nums1[i] != x) {
+                return null;  // Inconsistent difference found
+            }
+        }
+        
+        return x;
+    }
+```
+#### Conclusion
+The above solutions determine the integer x that was added to each element of nums1 to obtain nums2. 
+By ensuring consistency across the entire array, we validate the difference and return the result. 
+Adjustments for different languages and edge cases ensure robustness across various inputs.