|
| 1 | +--- |
| 2 | +id: largest-element-in-array |
| 3 | +title: Largest Element In Array |
| 4 | +sidebar_label: Largest-Element-In-Array |
| 5 | +tags: |
| 6 | + - Arrays |
| 7 | + - Data Structure |
| 8 | +description: "This tutorial covers the solution to the Largest Element In Array problem from the GeeksforGeeks website, featuring implementations in C++." |
| 9 | +--- |
| 10 | +## Problem Description |
| 11 | +Given an array `arr`, the task is to find the largest element in it. |
| 12 | + |
| 13 | +## Examples |
| 14 | + |
| 15 | +**Example 1:** |
| 16 | + |
| 17 | +``` |
| 18 | +Input: arr= [1, 8, 7, 56, 90] |
| 19 | +Output: 90 |
| 20 | +Explanation: The largest element of given array is 90. |
| 21 | +``` |
| 22 | + |
| 23 | +**Example 2:** |
| 24 | + |
| 25 | +``` |
| 26 | +Input: arr = [5, 5, 5, 5] |
| 27 | +Output: 5 |
| 28 | +Explanation: The largest element of given array is 5. |
| 29 | +``` |
| 30 | + |
| 31 | +## Your Task |
| 32 | + |
| 33 | +You don't need to read input anything. Your task is to complete the function `largest()` which takes the array `arr` and an size of array as `n` as input parameters and returns the largest number. |
| 34 | + |
| 35 | +Expected Time Complexity: O(n) |
| 36 | + |
| 37 | +Expected Auxiliary Space: O(1) |
| 38 | + |
| 39 | +## Constraints |
| 40 | + |
| 41 | +* `1 <= arr.size()<= 10^5` |
| 42 | + |
| 43 | +## Problem Explanation |
| 44 | + |
| 45 | +The task is to traverse the whole array and find the largest element of that array. |
| 46 | + |
| 47 | +## Code Implementation |
| 48 | + |
| 49 | +### C++ Solution |
| 50 | + |
| 51 | + |
| 52 | +```cpp |
| 53 | +class Solution |
| 54 | +{ |
| 55 | +public: |
| 56 | + int largest(vector<int> &arr, int n) |
| 57 | + { |
| 58 | + int maxi = INT_MIN; |
| 59 | + for(int i=0; i<n; i++){ |
| 60 | + maxi = max(arr[i], maxi); |
| 61 | + } |
| 62 | + return maxi; |
| 63 | + } |
| 64 | +}; |
| 65 | +``` |
| 66 | + |
| 67 | +```java |
| 68 | +public class Solution { |
| 69 | + public int largest(int[] arr) { |
| 70 | + int maxi = Integer.MIN_VALUE; |
| 71 | + for (int i = 0; i < arr.length; i++) { |
| 72 | + maxi = Math.max(arr[i], maxi); |
| 73 | + } |
| 74 | + return maxi; |
| 75 | + } |
| 76 | +} |
| 77 | + |
| 78 | +``` |
| 79 | + |
| 80 | +```python |
| 81 | +class Solution: |
| 82 | + def largest(self, arr): |
| 83 | + maxi = float('-inf') |
| 84 | + for i in range(len(arr)): |
| 85 | + maxi = max(arr[i], maxi) |
| 86 | + return maxi |
| 87 | + |
| 88 | +``` |
| 89 | + |
| 90 | +```javascript |
| 91 | +class Solution { |
| 92 | + largest(arr) { |
| 93 | + let maxi = -Infinity; |
| 94 | + for (let i = 0; i < arr.length; i++) { |
| 95 | + maxi = Math.max(arr[i], maxi); |
| 96 | + } |
| 97 | + return maxi; |
| 98 | + } |
| 99 | +} |
| 100 | + |
| 101 | +``` |
| 102 | + |
| 103 | +```typescript |
| 104 | +class Solution { |
| 105 | + largest(arr: number[]) { |
| 106 | + let maxi = -Infinity; |
| 107 | + for (let i = 0; i < arr.length; i++) { |
| 108 | + maxi = Math.max(arr[i], maxi); |
| 109 | + } |
| 110 | + return maxi; |
| 111 | + } |
| 112 | +} |
| 113 | + |
| 114 | +`` |
| 115 | + |
| 116 | +## Time Complexity |
| 117 | + |
| 118 | +* The time complexity is $$O(n)$$ where n is the length of the input array. This is because we are iterating through the array once to find the maximum element. |
| 119 | + |
| 120 | +## Space Complexity |
| 121 | + |
| 122 | +* The auxiliary space complexity is $O(1)$ which means the space required does not change with the size of the input array. This is because we are only using a fixed amount of space to store the maximum element and the index. |
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