Not possible to detach interrupt

The `onDetect()` method can be used to attached interrupts so that when a touch event is detected by the GT911, the specified sub routine is ran specified by `handler` in the function below. 
https://github.com/arduino-libraries/Arduino_GigaDisplayTouch/blob/4101b8a1f4a1d047228fafb36b6fd203c7481e23/src/Arduino_GigaDisplayTouch.cpp#L173-L177


An example of how to use the interrupt is given in `Touch_IRQ.ino` example.
https://github.com/arduino-libraries/Arduino_GigaDisplayTouch/blob/4101b8a1f4a1d047228fafb36b6fd203c7481e23/examples/Touch_IRQ/Touch_IRQ.ino#L47
https://github.com/arduino-libraries/Arduino_GigaDisplayTouch/blob/4101b8a1f4a1d047228fafb36b6fd203c7481e23/examples/Touch_IRQ/Touch_IRQ.ino#L24-L34

It is not possible to detach the interrupt, using the current public methods. Detaching interrupts is useful for:
- Using `delay()`
- Sending data over serial, without competing with the interrupt pin

	void Arduino_GigaDisplayTouch::onDetect(void (handler)(uint8_t, GDTpoint_t)) {
	_gt911TouchHandler = handler;
	t.start(callback(&queue, &events::EventQueue::dispatch_forever));
	_irqInt.rise(queue.event(mbed::callback(this, &Arduino_GigaDisplayTouch::_gt911onIrq)));
	}

	void gigaTouchHandler(uint8_t contacts, GDTpoint_t* points) {
	Serial.print("Contacts: ");
	Serial.println(contacts);

	if (contacts > 0) {
	/* First touch point */
	Serial.print(points[0].x);
	Serial.print(" ");
	Serial.println(points[0].y);
	}
	}

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Not possible to detach interrupt #8

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Not possible to detach interrupt #8

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