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| 1 | +package com.thealgorithm.stacks; |
| 2 | + |
| 3 | +import java.util.Arrays; |
| 4 | +import java.util.Stack; |
| 5 | + |
| 6 | +/** |
| 7 | + * @author: Subham Santra |
| 8 | + */ |
| 9 | +public class LargestSubMatrixWithRearrangements { |
| 10 | + public int largestSubmatrix(int[][] matrix) { |
| 11 | + int m = matrix.length; |
| 12 | + int n = matrix[0].length; |
| 13 | + int[][] prefixSum = new int[m][n]; |
| 14 | + |
| 15 | + System.arraycopy(matrix[0], 0, prefixSum[0], 0, n); |
| 16 | + |
| 17 | + for (int i = 1; i < m; ++i) { |
| 18 | + for (int j = 0; j < n; ++j) { |
| 19 | + prefixSum[i][j] = matrix[i][j] == 0 ? 0 : prefixSum[i - 1][j] + matrix[i][j]; |
| 20 | + } |
| 21 | + } |
| 22 | + |
| 23 | + int result = 0; |
| 24 | + |
| 25 | + for (int i = 0; i < m; ++i) { // O(R) |
| 26 | + // O(ClogC) + O(C) = O(ClogC) |
| 27 | + Arrays.sort(prefixSum[i]); // O(ClogC) |
| 28 | + result = Math.max(result, largestHistogram(prefixSum[i])); // O(C) |
| 29 | + } |
| 30 | + |
| 31 | + // Overall TC : O(RClogC) -> O(mn(log n)) |
| 32 | + return result; |
| 33 | + } |
| 34 | + |
| 35 | + private int largestHistogram(int[] arr) { |
| 36 | + Stack<int[]> stack = new Stack<>(); |
| 37 | + int[] temp = new int[arr.length]; |
| 38 | + for (int i = 0; i < arr.length; ++i) { |
| 39 | + int backIndex = i; |
| 40 | + while (!stack.isEmpty() && (stack.peek()[0] > arr[i])) { |
| 41 | + backIndex = stack.pop()[1]; |
| 42 | + } |
| 43 | + temp[i] = arr[i] * (backIndex - i + 1); |
| 44 | + stack.push(new int[] {arr[i], backIndex, i}); |
| 45 | + } |
| 46 | + while (!stack.isEmpty()) { |
| 47 | + temp[stack.peek()[2]] = stack.peek()[0] * (arr.length - stack.peek()[2]); |
| 48 | + stack.pop(); |
| 49 | + } |
| 50 | + return Arrays.stream(temp).max().orElse(0); |
| 51 | + } |
| 52 | + |
| 53 | + public static void main(String[] args) { |
| 54 | + System.out.println( |
| 55 | + new LargestSubMatrixWithRearrangements() |
| 56 | + .largestSubmatrix(new int[][] {{1, 1, 0}, {1, 0, 1}})); |
| 57 | + |
| 58 | + System.out.println( |
| 59 | + new LargestSubMatrixWithRearrangements() |
| 60 | + .largestSubmatrix(new int[][] {{0, 0, 1}, {1, 1, 1}, {1, 0, 1}})); |
| 61 | + |
| 62 | + System.out.println( |
| 63 | + new LargestSubMatrixWithRearrangements() |
| 64 | + .largestSubmatrix(new int[][] {{1, 0, 1, 1, 0, 1}})); |
| 65 | + } |
| 66 | +} |
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