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lectures/scalar_dynam.md
@@ -293,12 +293,17 @@ $$
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Obviously every globally stable steady state is also locally stable.
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-We will see examples below where the converse is not true.
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+Here is an example where the converse is not true.
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+```{prf:example}
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+Consider the self-map $g$ on $\mathbb{R}$ defined by $g(x)=x^2$. The fixed point $1$ is not stable.
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+For example, $g^t (x)\to\infty$ for any $x>1$.
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+However, $0$ is locally stable, because $-1<x<1$ implies that $g^t (x)\to 0$ as $t\to\infty$.
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+Since we have more than one fixed point, $0$ is not globally stable.
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+```
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## Graphical analysis
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