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Unable to access extended properties in constructor #1617

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@brenthoneybone

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@brenthoneybone

I'm not sure if this is an intention of typescript or not but acts differently to how I would've expected.

If i have a base class and extend it, overriding some base class properties, then want to work with the properties in the child class constructor I still access the parent properties.

This is shown in the below basic example.

class Base {

    public myVar:string = 'Base';

    public constructor() {
        console.log(this.myVar);
    }

}

class Child extends Base {

    public myVar:string = 'Child';

}

var base:Base = new Base(); // 'Base' - As expected
var child:Child = new Child(); // 'Base' - I would've expected this to be 'Child'

console.log(base.myVar); // 'Base' - As expected
console.log(child.myVar); // 'Child' - As expected

This happens in the compiled JS because the super is called before the child properties are set:

function Child() {
    _super.apply(this, arguments);
    this.myVar = 'Child';
}

Is this intended? An issue? Or a trade off because of JS limitations? Thanks!

Note that if I do something like this, it works as I would've expected. However it feels like a bit of a hacky work around.

class Base {

    public myVar:string = 'Base';

    public constructor() {
        this.setup();
    }

    protected setup() {
        console.log(this.myVar);
    }

}

class Child extends Base {

    public myVar:string = 'Child';

    public constructor() {
        super();
        this.setup();
    }

}

var base:Base = new Base(); // 'Base'
var child:Child = new Child(); // 'Child' - Now as expected

console.log(base.myVar); // 'Base'
console.log(child.myVar); // 'Child'

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    By DesignDeprecated - use "Working as Intended" or "Design Limitation" insteadCanonicalThis issue contains a lengthy and complete description of a particular problem, solution, or design

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