Merge pull request #67 from Jer3myYu/java-solutions-tries

Java Chapter 12: Tries

Author: Destiny-02

java/Tries/DesignATrie.java

@@ -0,0 +1,60 @@
+import java.util.HashMap;
+import java.util.Map;
+
+class TrieNode {
+    Map<Character, TrieNode> children;
+    boolean isWord;
+    public TrieNode() {
+        this.children = new HashMap<>();
+        this.isWord = false;
+    }
+}
+
+public class DesignATrie {
+    TrieNode root;
+
+    public DesignATrie() {
+        this.root = new TrieNode();    
+    }
+
+    public void insert(String word) {
+        TrieNode node = this.root;
+        for (char c : word.toCharArray()) {
+            // For each character in the word, if it's not a child of
+            // the current node, create a new TrieNode for that
+            // character.
+            node.children.putIfAbsent(c, new TrieNode());
+            node = node.children.get(c);
+        }
+        // Mark the last node as the end of a word.
+        node.isWord = true;
+    }
+
+    public boolean search(String word) {
+        TrieNode node = this.root;
+        for (char c : word.toCharArray()) {
+            // For each character in the word, if it's not a child of
+            // the current node, the word doesn't exist in the Trie.
+            if (!node.children.containsKey(c)) {
+                return false;
+            }
+            node = node.children.get(c);
+        }
+        // Return whether the current node is marked as the end of the
+        // word.
+        return node.isWord;
+    }
+
+    public boolean hasPrefix(String prefix) {
+        TrieNode node = this.root;
+        for (char c : prefix.toCharArray()) {
+            if (!node.children.containsKey(c)) {
+                return false;
+            }
+            node = node.children.get(c);
+        }
+        // Once we've traversed the nodes corresponding to each
+        // character in the prefix, return True.
+        return true;
+    }
+}

java/Tries/FindAllWordsOnABoard.java

@@ -0,0 +1,69 @@
+import java.util.ArrayList;
+import java.util.HashMap;
+import java.util.List;
+import java.util.Map;
+
+class TrieNode {
+    Map<Character, TrieNode> children;
+    String word;
+    public TrieNode() {
+        this.children = new HashMap<>();
+        this.word = null;
+    }
+}
+
+public class FindAllWordsOnABoard {
+    public List<String> findAllWordsOnABoard(char[][] board, String[] words) {
+        TrieNode root = new TrieNode();
+        // Insert every word into the trie.
+        for (String word : words) {
+            TrieNode node = root;
+            for (char c : word.toCharArray()) {
+                node.children.putIfAbsent(c, new TrieNode());
+                node = node.children.get(c);
+            }
+            node.word = word;
+        }
+        List<String> res = new ArrayList<>();
+        // Start a DFS call from each cell of the board that contains a
+        // child of the root node, which represents the first letter of a
+        // word in the trie.
+        for (int r = 0; r < board.length; r++) {
+            for (int c = 0; c < board[0].length; c++) {
+                if (root.children.containsKey(board[r][c])) {
+                    dfs(board, r, c, root.children.get(board[r][c]), res);
+                }
+            }
+        }
+        return res;
+    }
+
+    private void dfs(char[][] board, int r, int c, TrieNode node, List<String> res) {
+        // If the current node represents the end of a word, add the word to
+        // the result.
+        if (node.word != null) {
+            res.add(node.word);
+            // Ensure the current word is only added once.
+            node.word = null;
+        }
+        char temp = board[r][c];
+        // Mark the current cell as visited.
+        board[r][c] = '#';
+        // Explore all adjacent cells that correspond with a child of the
+        // current TrieNode.
+        int[][] dirs = new int[][]{{-1, 0}, {1, 0}, {0, -1}, {0, 1}};
+        for (int[] d : dirs) {
+            int nextR = r + d[0];
+            int nextC = c + d[1];
+            if (isWithinBounds(nextR, nextC, board) && node.children.containsKey(board[nextR][nextC])) {
+                dfs(board, nextR, nextC, node.children.get(board[nextR][nextC]), res);
+            }
+        }
+        // Backtrack by reverting the cell back to its original character.
+        board[r][c] = temp;
+    }
+
+    private boolean isWithinBounds(int r, int c, char[][] board) {
+        return 0 <= r && r < board.length && 0 <= c && c < board[0].length;
+    }
+}

java/Tries/InsertAndSearchWordsWithWildcards.java

@@ -0,0 +1,57 @@
+import java.util.HashMap;
+import java.util.Map;
+
+class TrieNode {
+    Map<Character, TrieNode> children;
+    boolean isWord;
+    public TrieNode() {
+        this.children = new HashMap<>();
+        this.isWord = false;
+    }
+}
+
+public class InsertAndSearchWordsWithWildcards {
+    TrieNode root;
+
+    public InsertAndSearchWordsWithWildcards() {
+        this.root = new TrieNode();
+    }
+    
+    public void insert(String word) {
+        TrieNode node = this.root;
+        for (char c : word.toCharArray()) {
+            node.children.putIfAbsent(c, new TrieNode());
+            node = node.children.get(c);
+        }
+        node.isWord = true;
+    }
+
+    public boolean search(String word) {
+        // Start searching from the root of the trie.
+        return searchHelper(0, word, this.root);
+    }
+
+    private boolean searchHelper(int wordIndex, String word, TrieNode node) {
+        for (int i = wordIndex; i < word.length(); i++) {
+            char c = word.charAt(i);
+            // If a wildcard character is encountered, recursively
+            // search for the rest of the word from each child node.
+            if (c == '.') {
+                for (TrieNode child : node.children.values()) {
+                    // If a match is found, return true.
+                    if (searchHelper(i + 1, word, child)) {
+                        return true;
+                    }
+                }
+                return false;
+            } else if (node.children.containsKey(c)) {
+                node = node.children.get(c);
+            } else {
+                return false;
+            }
+        }
+        // After processing the last character, return true if we've
+        // reached the end of a word.
+        return node.isWord;
+    }
+}